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8x^2-29x+15=18
We move all terms to the left:
8x^2-29x+15-(18)=0
We add all the numbers together, and all the variables
8x^2-29x-3=0
a = 8; b = -29; c = -3;
Δ = b2-4ac
Δ = -292-4·8·(-3)
Δ = 937
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{937}}{2*8}=\frac{29-\sqrt{937}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{937}}{2*8}=\frac{29+\sqrt{937}}{16} $
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